# A Pinoy 2 Card System

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#1 4 January, 2017 - 19:45
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Joined: 1 month 3 weeks ago

#### A Pinoy 2 Card System

Hi, I am Mark Joseph, 24 and I am from the Philippines. I just want to share my 2 card system. I use the same idea as the two block system where a two pairs of cards could have the same image. The idea of my system is converting two cards into a 3 digit number since some of my images are not phonetically coded like 025, which is for me is a gift, 014 a heart, 901 striker from Mortal Kombat etc.

Suit Values
♠=1 ♥=2 ♣=3 ♦=4

Suit Combination Rules
For the 1st suit in the suit combination:
♣=5
♥ would be the red version of ♠
♦ would be the red version of ♣

For the Face Card
the 2nd digit would be the suit combination and the 3rd digit would be the index(#) of the 2nd card.

For the Suit Combination
the 2nd digit would be the index(#) of the 1st card and the 3rd would be the index(#) of the 2nd card.

First Digit
Q = 0 (because it is like zero)
J = 1 (because it is like a “t”)
(red ver.)
♠♠ ( ♥♠ ) = 2 (because 1+1=2)
♠♥ ( ♥♥ ) = 3 (because 1+2=3)
♠♣ ( ♥♣ ) = 4
♠♦ ( ♥♦ ) = 5
♣♠ ( ♦♠ ) = 6 (because ♣ is in the 1st position it is 5; 5+1=6)
♣♥ ( ♦♥ ) = 7
♣♣ ( ♦♣ ) = 8
♣♦ ( ♦♦ ) = 9

For the K♠ + 2nd card, the rule is subtracting the suit values to get the first 2 digits and the index (#) of the 2nd card would be the 3rd digit.
(red ver.)
K♠ #♠ (K♥ #♠) = 00# (because 1-1 = 0)
K♠ #♥ (K♥ #♥) = 01# (because 2-1 = 1)
K♠ #♣ (K♥ #♣) = 10# (because 3-1 = 2, converting to binary digits that would be 10)
K♠ #♦ (K♥ #♦) = 11# (because 4-1 = 3, converting to binary digits that would be 11)

Examples:
4♠ 2♠ = 242 = 4♥ 2♠
5♣ 8♥ = 758 = 5♦ 8♥
J♣ 3♦ =193 = J♦ 3♦
K♠ 9♦ = 119 = K♥ 9♦
K♠ 5♥ = 015 = K♥5♥
Q♠ 4♦ = 054 = Q♥ 4♦

The 352 images outside the 1000 digit system would be the J, Q, K in the 2nd card and K♣.
(We are free to use whatever method we like for the 352 images).
# (suit) J (suit) = 100 images
# (suit) Q(suit) = 100 images
# (suit) K(suit) = 100 images
a total of 300 images
K♣ #♠ (K♦ #♠) = 13 images
K♣ #♥ (K♦ #♥) = 13 images
K♣ #♣ (K♦ #♣) = 13 images
K♣ #♦ (K♦ #♦) = 13 images
a total of 52 images

Mine is:

The J,Q and K in the 2nd card:
J = “t,d” sound
Q = “s,c,z” sound
K = “k,g” sound

I use the ben system for my 1000 digit images. So to avoid having images that have the same phonetic code, I use the major system for the face cards.

Example:
811 = “vat” so for me avatar
80J = “f s t” so for me fast and furious; Paul Walker

For the K♣ + 2nd card:
I just use the 2nd card as the clue to create the image

Example:
K♣ 10♣ (K♦ 10♣) I convert the 2nd card to number so that would be 30, so for me it would be Stephen Curry.

The one problem using 2 block system is the variable images per locus sometimes 1, 3, 6, or 8 but I have this idea that just came to my mind.

For example if the first 7 pairs of cards in a deck are all black first version, I put maximum of 3 images in the 1st locus, put the 3 images in the 2nd locus and put the last image in the 3rd locus .

What I do to remember that I made that changes is that I make the last image in the 1st locus interacts with the images in the 2nd locus and the last image in the 2nd locus interacts with the image in the 3rd locus.

So as you can see it is like a very long chain story of 7 images but in a different locus rather than putting all the 7 images in one locus which is very risky. I dont know if this works since i'm not yet fast with my system.

Thanks, I hope this will help.

10 January, 2017 - 23:47
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Joined: 5 years 3 months ago

Hi Mark Joseph,
So are you saying you haven't used this system to memorise a deck of cards yet?

Jimbo

11 January, 2017 - 20:04
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Joined: 1 month 3 weeks ago

Hello. I have used it. But i am not yet fast.

24 February, 2017 - 00:54
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Joined: 2 weeks 4 days ago

hmmm. sounds like the 52 images from the Kclubs+2nd card can be used also as an image for a single card and is useful for those surprise event in xmt like the card image event.
nice work.

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